Percentage Yield Question

The thermite reaction has been used to weld railroad rails, make bombs, and ignite solid rocket fuel. The equation of the reaction is:

Fe2O3 + 2Al --> 2Fe + Al2O3

1) What is the theoretical yield of iron if 100.0 g of Fe2O3 is used?

2) What is the percentage yield if 52.3 g of iron is actually produced?

Thank you!

1.
100.0g Fe2O3 divided by molar mass Fe2O3 is moles Fe2O3
this number multiplied by 2 is moles Fe yielded (ratio is 1:2)
multiply this number by molar mass of Fe to get g Fe produced (theoretical yield)

2.
52.3 divided by answer to 1. times 100

Percentage Yield = (mass of Actual Yield / mass of Theoretical Yield) x 100%

1.) 100.0 g
2.) = (52.3/100.0) * 100 = 52.3%