Calculate the volume that will be occupied by 350.0 mL of oxygen, measured at 720.0 mm, when the pressure is changed to 630.0 mm.
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This is a standard text book problem.
Assuming ideal gas behaviour
We use the relation, P.V = NRT
Since Temperature (T) change is not mentioned, I have to take it as a constant.
Therefore we get P1/V1 = P2/V2 - also termed Boyles' law
where P1 = 720mm, V1 = 350mL and P2 = 630mm
We have to find V2
V2 = P2*V1/P1
= 630*350/720
= 306.25 mL
Assuming ideal gas behaviour
We use the relation, P.V = NRT
Since Temperature (T) change is not mentioned, I have to take it as a constant.
Therefore we get P1/V1 = P2/V2 - also termed Boyles' law
where P1 = 720mm, V1 = 350mL and P2 = 630mm
We have to find V2
V2 = P2*V1/P1
= 630*350/720
= 306.25 mL