.6 probability of answering a question right. What's the probability of answering 0-5 questions right

A girl has 5 questions on a true/false test. She has a .6 probability of getting the question right. Let P(x) be the probability of getting exactly x of the answers correct. Calculate P(0) through P(5).

I have it up to the equations,'


P(0) = 5C0 (.4)^5
P(1)=5C1 (.6) (.4)^4
p(2)=5c2 (.6)^2 (.4)^3
p(3)=5c3 (.6)^3 (.4)2
p(4)=5c4 (.6)^4 (.4)
p(5)=5c5 (.6)^5

What do I do now? Did I even do the last part right?

Correct except for the typo in p(3).

Now its just calculation. use a calculator to do exponents and multiplications. Some calculators do combinations. otherwise the formula for nCr is:

N!/[R! * (N-R)!]
where x! is factorial or the multiplication of all the numbers from 1 to x. That is 6!=6*5*4*3*2*1

Simplify:
nCr = n!/[ r! * (n-r)!]
5C0= 5!/(0!*5!)= 1.... Note: 0! = 1
.4^5= .01024
So P(0)= 1(.01024)= .01024

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You can also find the coefficients on the fifth row of Pascal's triangle:
1. ..5..10...10....5....1
So p(1)= 5(.6)(.4^4)= .0768

I hope this helps!