Can someone solve this quadratic equation using the quadratic forumula: x(x+6)=35
Show me the working please
Show me the working please
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x(x+6)=35
x^2+6x=35
x^2+6x+9=35+9
(x+3)^2=44
x+3=+-√44 = +-2√11
x=-3+-2√11
So x=-3-2√11 or x= -3+2√11
x^2+6x=35
x^2+6x+9=35+9
(x+3)^2=44
x+3=+-√44 = +-2√11
x=-3+-2√11
So x=-3-2√11 or x= -3+2√11
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x(x+6) = 35
==> x^2 +6x -35 = 0
==> x = (-6 +/- √(36 + 4*35))/2
==> x = (-6 +/- √176)/2
so x = -3 + 2√11 or -3 - 2√11
==> x^2 +6x -35 = 0
==> x = (-6 +/- √(36 + 4*35))/2
==> x = (-6 +/- √176)/2
so x = -3 + 2√11 or -3 - 2√11