How do I solve 4-2t/6t^2 = 1

would the answer be 6t^2 + 2t -4 = 0 can someone elaborate on this

I think you mean (4 - 2t)/6t^2 = 1
multiply both sides by 6t^2
4 - 2t = 6t^2
6t^2 + 2t - 4 = 0 ok, you got that far

(3t - 2)(2t + 2) = 0
t = -1
or
t = 2/3

Question is incorrect and should be shown as :-

(4 - 2t) / (6t²) = 1

4 - 2t = 6t²

6t² + 2t - 4 = 0

3t² + t - 2 = 0

(3t - 2) (t + 1) = 0

t = 2/3 , t = - 1

Ambiguous. My first guess is
4 – (2t/6t^2) = 1
3 – (1/3t) = 0
9t = 1
t = 1/9

(4 - 2t)/(6t^2) = 1
6t^2 = 4 - 2t
6t^2 + 2t - 4 = 0
(t + 1)(6t - 4) = 0
Solutions:
t = -1
t = 2/3