What is the molality of a 5.83M aqueous sulfuric acid, H2SO4, solution
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# What is the molality of a 5.83M aqueous sulfuric acid, H2SO4, solution

[From: ] [author: ] [Date: 11-04-23] [Hit: ]
69m.-In 1L you have 5.83 moles of H2SO4, which is 571.9 g,5.......
The density of the solution is 1.33 g/mL. I keep getting an answer of 4.83m, but the key says that the answer is 7.69m.

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In 1L you have 5.83 moles of H2SO4, which is 571.9 g, based on
5.83 mol x 98.1 g/mol.

Next find the mass of water in 1L of the solution knowing that the solution has a mass of 1.33 g per mL or 1330 grams per liter.

1330 g - 572 g = 758 grams of water, or 0.758 kg of water.

Molality is moles of solute per kilogram of solvent...
5.83 mol / 0.758 kg = 7.69 molal

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You are correct!
1
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