Number of moles of HCl in 50.0ml of 1.00M HCl

50.0 ml = 0.0500L
Checking answer.

M= mol sol/ L sol'n

1.00 M HCl= x/.0500 L

1.00(.0500) = x

x = .05 mol sol/ 50 mL sol'n

Therefore, there are .05 mol of HCl in 50.0mL of 1.00M HCl

1.00 moles HCl / 1 L = X moles HCl / 0.050 L HCl

X = 0.05 moles HCl in 50.0 mL

number of moles, n = concentration,c/volume,v
n=1/0.0500 = 20mol.