step 1 : 2A -------> A2
Step 2: A2 + B ---------> C+2D
what would the rate law be if step 2 is SLOW and step 1 is fast?
Step 2: A2 + B ---------> C+2D
what would the rate law be if step 2 is SLOW and step 1 is fast?
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Since the rate law is determined by the slow step, the rate law would be:
Rate = k[A2][B]
But [A2] is proportional to [A]^2
So, Rate = k[A]^2[B] would be the rate law.
Rate = k[A2][B]
But [A2] is proportional to [A]^2
So, Rate = k[A]^2[B] would be the rate law.
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The SLOW step is the rate-determining step.
rate = k[A]^2[B]
rate = k[A]^2[B]