only not really, its just me and my MasteringChemistry homework. but i do have a problem with one question.
If the density of water is 1.00 g/mL and the density of mercury is 13.6 g/mL , how high a column of water in meters can be supported by standard atmospheric pressure?
could someone help me set this up so i can work it out? density doesnt fit into either the combined gas law, or the pv=nRT law (i dont remember the name) and those are the two formulas we learned for gases (the sections we are on).
If the density of water is 1.00 g/mL and the density of mercury is 13.6 g/mL , how high a column of water in meters can be supported by standard atmospheric pressure?
could someone help me set this up so i can work it out? density doesnt fit into either the combined gas law, or the pv=nRT law (i dont remember the name) and those are the two formulas we learned for gases (the sections we are on).
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No PV=nRT is not applicable. Someone is trying to hide in a corner on you.
1 atmosphere = 760 mm Hg = 76 cm Hg
The density of water = 1 gram / cc
The density of Hg = 13.grams / cc
Now lets try and set up a ratio.
1 cc of Hg = 13.6 cm high of water.
76 cc Hg = x
x = 13.6 * 76
x = 1033.6 cm of water.
1033.6 cm [ 1 m/100 cm] = 10.336 meters of water to equal the height of 76 cm of Hg.
1 atmosphere = 760 mm Hg = 76 cm Hg
The density of water = 1 gram / cc
The density of Hg = 13.grams / cc
Now lets try and set up a ratio.
1 cc of Hg = 13.6 cm high of water.
76 cc Hg = x
x = 13.6 * 76
x = 1033.6 cm of water.
1033.6 cm [ 1 m/100 cm] = 10.336 meters of water to equal the height of 76 cm of Hg.