Hi,
I am a bit confused about number of triangles for example: Determine the number of Triangles with the given parts:
a=11
b=6
c=8
Ans: 1 triangle
or
B= 65.7 deg
b= 4.42
a=17.5
Ans: No solution
I know how to find the other angles by using law of sines and cosins. I mean in both questions a > b. So how in first question one triangle is formed and in the second no Triangle is formed? Please explain. Thanks.
I am a bit confused about number of triangles for example: Determine the number of Triangles with the given parts:
a=11
b=6
c=8
Ans: 1 triangle
or
B= 65.7 deg
b= 4.42
a=17.5
Ans: No solution
I know how to find the other angles by using law of sines and cosins. I mean in both questions a > b. So how in first question one triangle is formed and in the second no Triangle is formed? Please explain. Thanks.
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When you use the Sine Law to calculate the sine of the angle opposite side a, the answer is 3.6+
The sine of an angle must be between -1 and +1 inclusive.
Therefore the angle opposite a does not exist ==> no triangle.
The sine of an angle must be between -1 and +1 inclusive.
Therefore the angle opposite a does not exist ==> no triangle.