Please help me verify this identity? tan²x - sin² = tan²x sin²x

Remember these identities.
tan²x = sin²x / cos²x
sin²x = 1 - cos²x

= tan²x - sin²x
= [sin²x/cos²x] - sin²x
= (sin²x - sin²xcos²x) / cos²x
= sin²x(1 - cos²x) / cos²x
= tan²xsin²x (Verified)

Have a good day.

tan^2x = sin^2x/cos^2x

lhs = sin^2x [1 - cos^2x]/cos^2x

but 1 - cos^2x = sin^2x
= sin^4x/cos^2x

= tan²x sin²x = rhs

tan²x - sin² x = (sin^2x/cos^2x) - sin^2x

....= (sin^2x - sin^2x*cos^2x) / cos^2x

....= sin^2x (1 - cos^2x) / cos^2x

....= sin^2x * sin^2x / cos^2x

....= sin^2x tan^2x