Essay; show all work. A simple dartboard has three areas… the main board has a radius of 9 inches, there is a circle with a radius of 5 inches, and the bullseye has a radius of 3 inches. What is the probability of a random dart landing inside the bullseye? Round to the nearest thousandth.

the middle board is a distraction
find the area of the outer board
pi(9)^2 = 254.34
pi(3)^2 = 28.26
the bullseye is inside the main board so to find the probability you have to find the area of JUST the main board
254.34  28.26 = 226.08
now divide to find the probability
28.26 / 226.08 = 0.125 or 1/8
find the area of the outer board
pi(9)^2 = 254.34
pi(3)^2 = 28.26
the bullseye is inside the main board so to find the probability you have to find the area of JUST the main board
254.34  28.26 = 226.08
now divide to find the probability
28.26 / 226.08 = 0.125 or 1/8

Area of the circle = PI (9)^2 = 81PI
Area of circle with radius 3 = PI (3)^2 = 9PI
Probability of bullseye = 9PI/81PI = 9/81 = 1/9 = 0.1111
Area of circle with radius 3 = PI (3)^2 = 9PI
Probability of bullseye = 9PI/81PI = 9/81 = 1/9 = 0.1111