cosӨ= 12/13
sin 2Ө= 2 sinӨcosӨ = 2 (5/13)(12/13) = 120/169
sin 2Ө= 2 sinӨcosӨ = 2 (5/13)(12/13) = 120/169

sin(2a) = 2sin(a)cos(a)
now since a is acute and cos(a) = sqrt(1  (5/13)^2)
=> cos(a) = 12/13
=> sin(2a) = 2sin(a)cos(a) = 2 * (5/13) * (12/13) = 120/169
now since a is acute and cos(a) = sqrt(1  (5/13)^2)
=> cos(a) = 12/13
=> sin(2a) = 2sin(a)cos(a) = 2 * (5/13) * (12/13) = 120/169

sin2theta = 2 sin theta cos theta
then you have to fin the value of cos theta
which is root 125/13^2 unit circle
12/13
then sin 2 theta = 2 * 5/13 * 12/13
= 12/169
then you have to fin the value of cos theta
which is root 125/13^2 unit circle
12/13
then sin 2 theta = 2 * 5/13 * 12/13
= 12/169