Evaluate the following definite integral: ∫ sqrt(4 + 3x)dx

Evaluate the following definite integral:

∫ sqrt(4 + 3x)dx
Note: ∫ (a=0 , b=7)

Any and all help is much appreciated! Thanks so much in advance!

Let u = 4+3x
Then you need to evaluate new a and b
a = 4, b = 25

Now it is ∫ sqrt(u)du from 4 to 25
Or ∫ u^1/2
=(2/3)u^(3/2) from 4 to 25
=(2/3)[(25)^(3/2) - (4)^(3/2)]
=(2/3)[125-8]
=(2/3)(117)
=234/3
=78

use exchange of variable to solve
u=4 + 3x
then do du
and exchange a and b with the new values
then you get a simple integration