Will you check my URGENT Algebra monomial work
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Will you check my URGENT Algebra monomial work

[From: ] [author: ] [Date: 11-04-22] [Hit: ]
2.3.4.5.6.7.......
!0 points best answer. Please help its due tomorrow. idk how to do it. Just give the answer to the wrong ones and explain how to do it i guess. Or just the answer or how to get the wrong ones RIGHT thanks soo much.Simplify the following
1. a^2 x a^2 a squared times a squared i put a^4
2. (3a^2b)^3 i put 27a^5b^3
3. n^2 x n^2 x n i put n^5
4. 7a^2 i put 49a^2
5. (3r^2s^3)(-5r^3s) i put -15r^5s^4
6. (3y^3)^3 i put 9y^2
7. (2/7a^2)(21a^5) i put 6a^7
8. (-a^3b)(-a^2b^2)(-ab^3) i put a^6b^6
9. 4h^3k^2/7 x 21hk^5/2 thats divided by seven times 21hk^5 divided by 2. I put 84h^4k^7/14 or divided by 14.
10. (5b^-4)(-3a^2b)(-a^3) i put -15a^5/b over or divided by b
11.8(y+4) i put 8y+32
12.2y(y+8) i put 18y
13. -5z(3y-4z) i put -60z^2y^1
14. -4t(t^2+7t-5) i put -140t^3
15.-7mr(12m-7r+5) i put -2940m^2r^1
16. a^3b(a^2-6) i put -6a^5b^1
17. 7x^2(x^3-7y) i put -14x^5y^1
18.pq^2(p^3q-9r) i put -9p^4q^3r^1
Thanks again sooo much. I really don't know if i have this right. Please hurry it's due tomorrow.

-
#2 = 27 a^6 b^3
#6 = 27y^9
#8 = -a^6 b^6 (you forgot the negative sign)
#9 True, but you can reduce it to 12 h^4 k^7
#10 = 15 a^5 b^-3, or 15 a^5 / b^3
#12 = 2y^2 + 16y
#13 = -15yz + 20z^2
#14 = -4t^3 - 28t^2 + 20t
#15 = -84m^2r + 49mr^2 - 35mr
#16 = a^5b - 6a^3b
#17 = 7x^5 - 49x^2y
#18 = p^4q^3 - 9pq^2r

So aside from not being careful about signs and such, you seem to understand the general idea of how to do #1 through #10. However, from #11 through #18, you aren't dealing with monomials anymore. Because there are multiple terms in one of the factors, you can't end up with a monomial as the product. You need to multiply the factor that's before the parenthesis by each term within the parenthesis in turn, and the product consists of the sum of all the terms. For example:

3a^2 (3a^4 - 2ab^2) = (3a^2 * 3a^4) - (3a^2 * 2ab^2) = 9a^6 - 6a^3b^2

Every problem from #11 through #18 works that way.
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