I need help answering this question!
Dana and Cathy are playing tennis. Given that the probability of Dana winning at least 1 out of 2 games is 0.3, what is the probability she will win at least 1 out of 4 games?
Dana and Cathy are playing tennis. Given that the probability of Dana winning at least 1 out of 2 games is 0.3, what is the probability she will win at least 1 out of 4 games?
-
Probability that they lose all of first two games = 1 - 0.3 = 0.7 .
Probability that they lose all games of the next two games = 0.7.
Probability that they lose all games out of 4 = 0.7 X 0.7 = 0.49 .
Probability that they would win at least 1 out of 4 games = 1 - 0.49 = 0.51 .
Probability that they lose all games of the next two games = 0.7.
Probability that they lose all games out of 4 = 0.7 X 0.7 = 0.49 .
Probability that they would win at least 1 out of 4 games = 1 - 0.49 = 0.51 .
-
X~bin(4, 0.3), X possible wins, x=0,1,2,3,4.
P{X≥1} = 1-P{X=0} = 1-(0.7)^4 = 1-0.24 = 0.76.
P{X≥1} = 1-P{X=0} = 1-(0.7)^4 = 1-0.24 = 0.76.
-
The probability that she will not win any out of 2 games is .7, so to find the probability that she wins at least one out of 4 games you solve: 1-0.7^2=1-0.49=.51