log (base 3) X + log (base 3) (x+9) = 5
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the sum of logs is the log of the product...
log (base 3) X + log (base 3) (x+9) = 5
log [base 3] [x(x + 9)] = 5
x^2 + 9x = 243
x^2 + 9x - 243 = 0
use the quadratic formula...
x = [- 9 ± √(1053)]/2
only the positive root is valid...
check
qed
by the way, upper and lower case letters represent different variables.
log (base 3) X + log (base 3) (x+9) = 5
log [base 3] [x(x + 9)] = 5
x^2 + 9x = 243
x^2 + 9x - 243 = 0
use the quadratic formula...
x = [- 9 ± √(1053)]/2
only the positive root is valid...
check
qed
by the way, upper and lower case letters represent different variables.