Find the derivatives at x = 0.2 of the following

cos^3(3x+2)sin(x-1)

you need to use chain rule and product rule

the derivative is -3(3x+2)sin^2(3x+2)sin(x-1) + (x-1)cos(x-1)cos^3(3x+2)

then just plug in 0.2 for x and you have answer

cos^3(3x+2)*cos(x-1) + sin(x-1)*3*cos^2(3x+2)*(-sin(3x+2))*3

= cos^3(3x+2)*cos(x-1) - 9sin(x-1)*cos^2(3x+2)*sin(3x+2))