The marbles are selected at random, one at a time, and are not replaced. What is the probability of selecting a blue and a red?-P(b1⋂r2) + P(r1⋂b2) = (6/10)*(3/9) + (3/10)*(6/9) = 2/5-In that order, or just in that combination?......
A box contains 3 red marbles, 6 blue marbles, and 1 white marble. The marbles are selected at random, one at a time, and are not replaced. What is the probability of selecting a blue and a red?
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P(b1⋂r2) + P(r1⋂b2) = (6/10)*(3/9) + (3/10)*(6/9) = 2/5
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In that order, or just in that combination?
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