Solve this equation: log[base 2] (x+3) = 3

please help!

log[base2] (x+3) = 3 - Rewrite the problem
2^log[base2](x+3) = 2^3 - Make each term the power of 2
x+3 = 2^3 - Cancel the base of the term on the left with the base of the log in the
- exponent on the left
x+3 = 8 - Perform 2 to the 3rd power
x = 5 - Subtract 3 from each side

Use the definition of logarithm and convert the equation to exponential form.
2^3 = (x+3)
8 = x+3
x = 5