A triangle, A,B as the base is 28 feet, A,C to the apex is 4 feet, angle A is a right angle, what is the angle C in degrees. I suspect it is simple, but I seemed to have skipped over trig.
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4 ft is the length of the adjacent side. 28 ft is the length of the opposite side.
tan(C) = (4 ft) / (28 ft) = 7 (because Soh Cah Toa)
Inverse trig functions eat lengths and poop angles, the reverse of normal. Therefore
tan^-1(7) = C = about 82 degrees
tan(C) = (4 ft) / (28 ft) = 7 (because Soh Cah Toa)
Inverse trig functions eat lengths and poop angles, the reverse of normal. Therefore
tan^-1(7) = C = about 82 degrees