5(2x-y+7)y^3 - y^2 - y =Same as before. The common term here is y.y(y^2-y-1)You can actually factor the inside too by using the rule (b+-sqrt(b^2-4ac))/2a but you end up with numbers under a square root so I dont think thats what your teacher wants.More writing as a polynomial:(x-4)^2Multiply (x-4)(x-4)You follow the rule FOIL First outer inner lastThis means is the case is (a+b)(c+d) then first you multiply first ac outer ad inner bc and then last bd. Together this is ac+ad+bc+bdSo in this case, x*x -4x -4x + 16That = x^2 -8x +16(x+3)(x+7)Same,......
3a^2(1-2b)
4x - 4 =
As with before, take out the common terms and then divide. In this case, it's 4.
4(x-1)
10x - 5y + 35 =
Same as before. The common term here is 5.
5(2x-y+7)
y^3 - y^2 - y =
Same as before. The common term here is y.
y(y^2-y-1)
You can actually factor the inside too by using the rule (b+-sqrt(b^2-4ac))/2a but you end up with numbers under a square root so I don't think that's what your teacher wants.
More writing as a polynomial:
(x-4)^2
Multiply (x-4)(x-4)
You follow the rule "FOIL" First outer inner last
This means is the case is (a+b)(c+d) then first you multiply "first" ac "outer" ad "inner" bc and then "last" bd. Together this is ac+ad+bc+bd
So in this case, x*x -4x -4x + 16
That = x^2 -8x +16
(x+3)(x+7)
Same, using FOIL method.
x^2 + 7x +3x +21
= x^2 +10x + 21
(x-2)(x+3)
FOIL method
x^2 + 3x -2x -5
= x^2 +x - 5
(2a-3)(3a - 4)
FOIL method
2a*3a -4*2a -3*3a +12
=6a^2 -8a -9a +12
=6a^2 -17a +12
Even if you have a learning disability, of course you can get 100%! Just practice and try to understand the process! Good luck :)
To write the polynomial just distribute, use the exponent rules or "FOIL" the values that are given. A polynomial always has an exponent.
For the factoring part, just take out like terms and keep simplifying by dividing or subtrating until you get a small term
It is simple just got to learn the pattern.
(5x^2 + 3x - 4) + (3x^2 - 8x - 2) treat how you would normally add and subract numbers BUT remember the variables (x^2,x) must go to their corresponding variables so( you can only add or subtract also divide and multiply if they have the same number of powers x^2 +x^2 = 2x^2.)
so..
(5x^2 + 3x - 4) + (3x^2 - 8x - 2)
=8x^2 - 5x -6
a(2-a) *remember distribution*
=2*a - a (2 a's and you take one away therefore you have 1 a left over)
=a
(a + b + 5)3b *distribute 3b to each value in the (..)*
= a*3b + 3b^2 + 5b
you can do the other factors yourself for practice...
(x-4)^2 (remember powers and that numner n; x^n is how many compies of x * )
= (x-4)*(x-4) (FOIL)
=x^2 - 4*x -4*x + 16 *simplify*
=x^2 -8*x +16
(2a-3)(3a - 4) (FOIL as well)
=6a^2 - 8a - 9a + 12 ( distribute one at a time...2a goes with 3a and -4. Then -3 goes with 3a and -4)
= 6a^2 -17a +12
Honestly if you have a learning disability i do not think you can get 100% but if you really try and understand the methods you probably can.
