It is a quadratic equation in the vertex form!!!
so it's vertex would be (h,k)
so it's vertex would be (h,k)
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y-k=a(x-h)^2
let Y=y-k & X=x-h
the eqn. becomes
Y=A (X)^2
which is parabola
let Y=y-k & X=x-h
the eqn. becomes
Y=A (X)^2
which is parabola
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standard equation for a parabola
a= determines how wide or narrow the parabola is
h= shift on x-axis
k= shift on y-axis
a= determines how wide or narrow the parabola is
h= shift on x-axis
k= shift on y-axis
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the basic quadratic curve first translated h right then stretched scale factor a in the direction parallel to the y-axis and then translated up k
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That's just a parabola shifted to the right h, moved up k, and compressed horizontally (or stretched vertically) a times.
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this is unanswerable since h k and a are not answered so it is impossible to answer
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Speaker of the House