Can you help Find the number of possible identification codes
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Can you help Find the number of possible identification codes

[From: ] [author: ] [Date: 11-05-06] [Hit: ]
so the total of 2 letters and 3 numbers is 26*26*10*10*10= 676,000. if you include the 26 lower case letters as well as upper case, it becomes 52*52*10*10*10=2,704,000.......
Employee identification codes at a company contain 2 letters followed by 3 digits. Find the number of possible identification codes.

The school's football team has a choice of different colored jerseys and different colored pants to wear for their uniforms. They have purple jerseys, white jerseys, and striped jerseys. The choices for the pants are purple or white. What is the probability that the team will select the white jerseys with purple pants?

Briana bought 3 fashion magazines, 2 exercise magazines, and 2 dance magazines. How many choices of magazines does she have to read?

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2 letters, 3 digits. OK, for UPPER case letters only, the first place has 26 possibilities. The second place has 26 possibilities for each of the 26 in the 1st place. Then, there are 1000 numbers for each, so the total of 2 letters and 3 numbers is 26*26*10*10*10= 676,000. if you include the 26 lower case letters as well as upper case, it becomes 52*52*10*10*10=2,704,000. For a computer, "A" and "a" are different.

As for the jerseys, 3 jerseys, 2 pants, means only 6 combinations, 3 each for each pair of pants, so the odds in a random draw are 1 in 6, 1 in 3 that a white jersey will be randomly selected, 1 in 2 that white pants will be randomly selected, for an overall chance of 1 in 6.

For the magazines, there is a 1 in 7 choice. There are simply 7 total, and you get to pick ONE, right? So, 1 in 7 that a particular magazine will be randomly selected. The odds of a particular TYPE of magazine is 3 in 7 for fashion, 2 in 7 for exercise and 2 in 7 for dance.
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