If 2 is the number of successes in a sequence of 4 independent Bernoulli trials with p = .5 and q = .5, calculate the probability of the stated event.
P(X = 2) = ?
P(X = 2) = ?
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Binomial Sampling Distribution:
P(n) = C(N,n) * p^n * (1-p)^(N-n)
with N =4 and n=2:
P(2) = C(4,2) * (1/2)^2 * (1/2)^2
P(2)= 6 * ( 1/ 4 ) * ( 1 / 4 ) = 6/16 = 3/8 = 0.375
Déjà vu
P(n) = C(N,n) * p^n * (1-p)^(N-n)
with N =4 and n=2:
P(2) = C(4,2) * (1/2)^2 * (1/2)^2
P(2)= 6 * ( 1/ 4 ) * ( 1 / 4 ) = 6/16 = 3/8 = 0.375
Déjà vu