A sphere has radius 8.4 meters. If you use pi=22/7 what will be the computed volume error in cubic cm

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A sphere has radius 8.4 meters. If you use pi=22/7 what will be the computed volume error in cubic cm

[From: ] [author: ] [Date: 11-05-07] [Hit: ]

Difference is -0.So difference is 999290 cm^3-Volume using 22/7 = (4/3)(22/7)(8.Actual Volume = 4/3 pi (8.So the difference is (4/3)(22/7 - pi)(8.Which is approximately equal to .Edit - Tims right - leaving this answer as is as a reminder that its always important to check your units!......

Actual volume is (4/3)pi(8.4)^3 m^3
Computed volume is (4/3)(22/7)(8.4)^3 m^3

Difference is -0.99929 m^3

One m^3 is equal to 100*100*100 cm^3

So difference is 999290 cm^3

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Volume using 22/7 = (4/3)(22/7)(8.4)^3
Actual Volume = 4/3 pi (8.4)^3

So the difference is (4/3)(22/7 - pi)(8.4)^3

Which is approximately equal to .9993

Edit - Tim's right - leaving this answer as is as a reminder that it's always important to check your units!

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