If x is an angle in standard position and it's terminal side passes through point (-3,2) find the exact value of sec x
Please show work and explain, I dont think I have learned this yet this year so please explain more, is there a formula ect.. what do you do exaclty. Thanks for your efforts! :)
Please show work and explain, I dont think I have learned this yet this year so please explain more, is there a formula ect.. what do you do exaclty. Thanks for your efforts! :)
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Click on the source and it has a picture explaining it, then read below.
So, if you can find the cosine of the angle, you do 1/cosx, and it should give you the secant.
Another way you could do it is if you use the triangle that the terminal side of the angle would make with the x axis. Imagine a line coming down from the terminal side to make a 90degree angle with it. You then know that you are going to the left 3, and up 2. You could use the Pythagorean theorem, (a squared + b squared = c squared) to find the hypotenuse. It would end up being the square root of 13. You should be able to find the cosine and then the secant from there if you know you SOH CAH TOA.. I really hope this helps!
So, if you can find the cosine of the angle, you do 1/cosx, and it should give you the secant.
Another way you could do it is if you use the triangle that the terminal side of the angle would make with the x axis. Imagine a line coming down from the terminal side to make a 90degree angle with it. You then know that you are going to the left 3, and up 2. You could use the Pythagorean theorem, (a squared + b squared = c squared) to find the hypotenuse. It would end up being the square root of 13. You should be able to find the cosine and then the secant from there if you know you SOH CAH TOA.. I really hope this helps!
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Draw a diagram. Label the horizontal side of the angle -3. Label the vertical side 2. Use the Pythagorean Theorem to find the hypotenuse.
h^2 = 9 + 4 = 13
h = √13
Now you know all three sides and can use them in the definition of the trig funcitons:
cos = adjacent / hypotenuse
1/cos = sec = hypotenuse/adjacent
sec(x) = (√13)/-3
Draw a diagram. Label the horizontal side of the angle -3. Label the vertical side 2. Use the Pythagorean Theorem to find the hypotenuse.
h^2 = 9 + 4 = 13
h = √13
Now you know all three sides and can use them in the definition of the trig funcitons:
cos = adjacent / hypotenuse
1/cos = sec = hypotenuse/adjacent
sec(x) = (√13)/-3