Find the factors of 2a2 + 9a − 18

Find the factors of 2a2 + 9a − 18

2a^2 + 9a - 18 = 0

(2a - 3)(a + 6) = 0; set each factor = to 0

2a - 3 = 0; add 3 to each side
2a - 3 + 3 = 0 + 3; simplify
2a = 3; divide both terms by 2
2a/2 = 3/2; simplify
a = 3/2 <-----------first answer

a + 6 = 0; subtract 6 from both sides
a + 6 - 6 = 0 - 6; solve
a = -6 <------------second answer

Blessings

(2a+3)(a-6) = 0.

expanded makes 2a^2 - 12a + 3a - 18 = 2a^2 +9a - 18.

2a+3 = 0. a = -1.5
and a-6 =0. a = 6

(2a-3)(a+6)
a= -6, 3/2

(a+6)(2a-3)