Given the probability distribution of the number of absent days per one plant.
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Given the probability distribution of the number of absent days per one plant.

[From: ] [author: ] [Date: 11-05-08] [Hit: ]
025+3*0.310+4*0.340+5*0.20+6*… 3.......
x---|---P(x)
0---|---0,05
2---|---0,025
3---|---0,310
4---|---0,340
5---|---0,20
6---|---0,080
7---|---0,001


To calculate :
- P (2 5) and P (x <4),
-Expected value, and
-Typical value.

Thanks foe your help ....Have a nice day. :D

-
P(2 P(x>5) = 0.080+0.001 = 0.081
E(x) = 0*0.05+2*0.025+3*0.310+4*0.340+5*0.20+6*… 3.827
typical value = 4
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