a^2=b^2+c^2-(2bcxcosA)
7^2=8^2+6^2-(2x6x8xcosA)
can someone finish it from there please...
I managed to get it down to 96cosA=63 and had no clue how to finish it.
7^2=8^2+6^2-(2x6x8xcosA)
can someone finish it from there please...
I managed to get it down to 96cosA=63 and had no clue how to finish it.
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96 cos A = 63 is NOT correct...show your work to learn your mistake !
96 cos A = 51 is the correct equation from your data...
cos A = (51/96)
A = arccos (51/96)
get out your calculator...
A ≈ 57.91º
show your work...
96 cos A = 51 is the correct equation from your data...
cos A = (51/96)
A = arccos (51/96)
get out your calculator...
A ≈ 57.91º
show your work...
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49 = 64 + 36 - 96cosA
=> 96cosA = 64 + 36 - 49 = 51
So, cosA = 51/96
=> A = invcos(51/96) = 57.9 degrees
:)>
=> 96cosA = 64 + 36 - 49 = 51
So, cosA = 51/96
=> A = invcos(51/96) = 57.9 degrees
:)>
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96cosa=63
Cosa=63/96=21/32=0.656
A=cos inverse of 0.656=49 degrees
Cosa=63/96=21/32=0.656
A=cos inverse of 0.656=49 degrees