Anyone good at SIMPLIFYING (sqroot) ? 5STARS 10 pts

1) 3(sqroot)6 + 5(sqroot)54


2) 9
___________
5 - (sqroot)3

1) 3*√6 + 5√54
3*√6 + 5√(9*6)
3*√6 + 5*3√6
(3 + 5*3)√6
18√6

2) 9/(5 - √3)
9(5+√3)/(5 - √3)(5 + √3)
9(5+√3)/(25 - 3)
9(5+√3)/(22)
(45+9√3)/22
45/22 +(9√3)/22

1) 3(sqroot)6 + 5(sqroot)54
3(sqroot)6 +5(sqroot)9*(sqroot)6 [ because 9x6=54]
3(sqroot)6 +5x3(sqroot)6 [ root9 = 3]
3(sqroot)6 +15(sqroot)6
18(sqroot)6

2) 9/(5 - (sqroot)3)
9/(5 - (sqroot)3) x [5 + (sqroot)3]/[5 + (sqroot)3]
(45 + 9(sqroot)3) / (5 - (sqroot)3)(5 + (sqroot)3)
(45 + 9(sqroot)3) / (25-3)
(45 + 9(sqroot)3) / 22

1.
3 sqrt(6) + 5 sqrt(54) =
3 sqrt(6) + 5 sqrt(9*6) =
3 sqrt(6) + 5 sqrt(9) sqrt(6) =
3 sqrt(6) + 5 * 3 sqrt(6) =
3 sqrt(6) + 15 sqrt(6) =
18 sqrt(6)

2.
9 / (5 - sqrt(3))) =
9 (5 + sqrt(3)) / ((5 - sqrt(3))(5 + sqrt(3)) =
9 (5 + sqrt(3)) / (25 - 3)
= (45 + 9 sqrt(3)) / 22

1)
3sq6 + 5sq54
3sq6 + 15sq6
18sq6

1. 18 sqr. 6

3[(6)^1/2] +5[(54)^1/2]
=3[(6)^1/2]+15[(6)^1/2]
=18 [(6)^1/2]

for number two the answer would be 3.