Newton Raphson - A level Further Maths
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Newton Raphson - A level Further Maths

[From: ] [author: ] [Date: 11-05-08] [Hit: ]
For Newton Raphson method, let F(x) = x^3+5x-7,......
Dear all,
The question is in the link below. I have done part 1 already, it was a spiral that converges on alpha.

http://imageshack.us/photo/my-images/98/newtonraphson.jpg/

How do I do B? I have used f(x) and f'(x) and put them into the form x - f(x)/f'(x) for both forms. How would I explain how they converge?

Any help would be greatly appreciated.

Thank you in advance,
Jon

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You are not expected to use the Newton formula, but the simple
iteration formulas given in (a). x(n+1)=G(x(n))
These will converge to the root a if |G'(a)|<1, and use the given approximation
a=1. Find G'(x) where G(x)=7/(x^2+5) , giving -14x/(2x+5)^2
So G'(1) =-2/7 and |G'(1)|<1 so procedure converges to a.
Do the same with (7-x^3)/5 you get |G'(1)|=3/5
The one with the smaller G' converges more quickly.
If this is an MEI question look it up in the course book in Iterative Processes.

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this is not a Newton Raphson formula. it is an iteration.

x=G(x),
x_(n+1)=G(x_n)

For Newton Raphson method, let F(x) = x^3+5x-7, and do
x_(n+1)=x_n - f(x_n))/f'(x_n)

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I know it
1
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