Have i done this maths right

The question is to put 0.123123 into a fraction. The last 123 i recurring. We haven't been told how to do this and i through my own methods got...

122877
-----------
1000000
Is that the right answer or have i done it all completely wrong?

I'm not exactly sure where you got 122877 from.

Here's how to solve:

x = 0.123123123123....
1000 x = 123.123123123123....

Now subtract x from 1000x:

1000x - x = 123.123123123.... - 0.123123123....
999x = 123
x = 123/999
x = 41/333

Now enter 41/333 into calculator and you will get 0.123123123...

just simply remember

0.123123...=123/999

the rule is, if you have 0.(abcdefg)(abcdefg)(abcdefg)... it equals abcdefg/9999999

how many digits in the repetition, then how many 9 to be divided.

if you have x=1234.567(54321)(54321)(54321)...
then x= 1234.567+(1/10000)*(0.5432154321...)
=1234567/1000+(54321/99999)/10000

its wrong.
The correct answer is 41/333
---
Go take a look at this site:
http://www.math-mate.com/chapter55.shtml
It teaches you how to convert recurring decimals into fractions ^_^ Good luck!!

123123/1000000 simplify yourself.

eg 0.5 = 5/10 , = 1/2

0.25 = 25/100, = 1/4