How do I solve this log problem

3^(7x+1)=7

3^(7x + 1) = 7

take the log of both sides...

(7x + 1) log 3 = log 7

7x log 3 = log 7 - log 3

x = [log 7 - log 3]/(7 log 3)

Get out your calculator...make a contribution...read your textbook...practice.

qed

( 7x + 1 ) log 3 = log 7

7x + 1 = log 7 / log 3

7x + 1 = 1.77

7x = 0.77

x = 0.11

(log7/log3)= 7x+1
(log3, 7 -1)/7=x
x=0.11

x= (log7/log3)/(7)+(1)

plz explain the question...