Integral from 0 to 1 of: 6x(sqrt(1 + x^2))
show steps please, thank you
show steps please, thank you
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∫ 6x√(1 + x²) dx = 6 ∫ x√(1 + x²) dx = 3 ∫ u√u du = 2 √u³ + C = 2√(x² + 1)³ + C
[substitution u=1+x² was used]
1
∫ 6x√(1 + x²) dx = 2√(1² + 1)³ - 2 √(0² + 1)³ = 4√2 - 2 = 3.657
0
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[substitution u=1+x² was used]
1
∫ 6x√(1 + x²) dx = 2√(1² + 1)³ - 2 √(0² + 1)³ = 4√2 - 2 = 3.657
0
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