How would you solve tan2xcotx-3=0?
Thanks in advance :)
Thanks in advance :)
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tan2x = 2tanx / 1 - tan^2x
cotx = 1 / tanx
Using these results you can simplify the equation to get:
2 / 1 - tan^2x = 3
3 tan^2x = 1
tan^2x = 1/3
So tanx = (+/-) 1/sqrt3
x = pi/6, 5pi/6, 7pi/6, 11pi/6
cotx = 1 / tanx
Using these results you can simplify the equation to get:
2 / 1 - tan^2x = 3
3 tan^2x = 1
tan^2x = 1/3
So tanx = (+/-) 1/sqrt3
x = pi/6, 5pi/6, 7pi/6, 11pi/6
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formula
tan2x=2tanx/(1-tan^2 x)
tan2xcotx-3=0 ---> tan^2 x = 1/3 , then easy to solve for x
tan2x=2tanx/(1-tan^2 x)
tan2xcotx-3=0 ---> tan^2 x = 1/3 , then easy to solve for x