Grade 12 math help, ASAP please!
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Grade 12 math help, ASAP please!

[From: ] [author: ] [Date: 11-05-10] [Hit: ]
Y!A only allows a certain length, so its cut off part of the question.=((x^2+y^2)/(x^2.((x^2.y^2)/(x^2+y^2))^2=(x^4.......
Simplify as much as possible:
((x^(-2))+(y^(-2)))^(-2)

Please help :)

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((x^(-2)) + (y^(-2)))^(-2)

Note this:
x^(-2) is the same thing as 1/x^(2)
y^(-2) is the same thing as 1/y^(2)
Because the same principle will be used later.

= ( (1/x^(2)) + (1/y^(2)) )^(-2)

Make the denominators the same:

= (( (1/x^2)*y^2/y^2) + (1/y^2)*x^2/x^2 )^(-2)

= (y^2/(x^2 y^2)) + (x^2/x^2 y^2))^(-2)

= ((y^2 + x^2) / (x^2 y^2))^(-2)

= (1) / (y^2 + x^2)^2 / (x^2 y^2)^2

= (1) / (y^2 + x^2)^2 / (x^4 y^4)

= (x^4 y^4) / (y^2 + x^2)^2

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would you be able to help me with this following question as well?


((4^2a)+(4^3a)+(4^3a)+(4^4a)… - ((4^2a)-(4^3a)-(4^3a)+(4^4a)

i know the answer is 4^(3a-1) but i am unsure what to do after this step (above)

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Thanks for best answer. :)

I'll be glad to help, but you need to put spaces like I did between the - and + signs for the entire problem to show up without the trailing dots .....

Y!A only allows a certain length, so it's cut off part of the question.

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((x^(-2))+(y^(-2)))^(-2)=(1/x^2+1/y^2)^-…
=((x^2+y^2)/(x^2.y^2))^-2
((x^2.y^2)/(x^2+y^2))^2=(x^4.y^4)/(x^4…
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keywords: help,please,ASAP,12,Grade,math,Grade 12 math help, ASAP please!
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