Solve each of the quadratic equations for their exact values by using the square root principle
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Solve each of the quadratic equations for their exact values by using the square root principle

[From: ] [author: ] [Date: 11-05-10] [Hit: ]
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a) 4x^2 -13 =0

b) -2(6x-3)^2 -12= - 48

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a)
4x^2 - 13 = 0
x^2 = 13/4
x = ±√(13) / 2

b)
-2(6x - 3)^2 - 12 = -48
(6x - 3)^2 = 18
6x - 3 = ±3√(2)
x = (1 ± √(2)) / 2

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