Let Θ = 150 degrees. Find the exact values of secΘ, tanΘ, and sinΘ
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Let Θ = 150 degrees. Find the exact values of secΘ, tanΘ, and sinΘ

[From: ] [author: ] [Date: 11-05-11] [Hit: ]
- tan 30° , sin 30°...you do know about the fundamental triangles ??......
Anyone know how to do this? care to explain please?

Thanks!

-
Reference Angle is 30°, Quadrant is 2 => sine positive, cosine negative

SinΘ = sin30° = 1/2
TanΘ = -tan30° = -√3/3
SecΘ = -sec30° = -1/cos30°= -2√3/3

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180 - 150 = 30°...thus - sec 30° , - tan 30° , sin 30°...

you do know about the fundamental triangles ??
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