Evaluate y' at the point (2,2).

For the equation given below, evaluate y' at the point (2,2).

4x^3-2y=ln(y)+28-ln(2).

y'at (2,2)=?

4x^3 - 2y = ln(y) + 28 - ln(2)
12x^2 * dx - 2 * dy = dy / y

x = 2
y = 2

12 * 2^2 * dx - 2 * dy = dy / 2
12 * 4 * dx = 2 * dy + dy / 2
48 * dx = dy * (2 + (1/2))
96 * dx = dy * (4 + 1)
96 * dx = dy * 5
dy/dx = 96 / 5
dy/dx = 19.2