I need help please alg. 2
Favorites|Homepage
Subscriptions | sitemap
HOME > Mathematics > I need help please alg. 2

I need help please alg. 2

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
What you do to the center, do to both of the other sides of the equations.Basically these inequalities say that this particular value of x is greater than -9/5,Hope this helps.......
in not sure how to do this

-8 < 5x + 1 < 7
---------
3

this is what i got but im not sure
-8 < 1(5x + 1) < 7
--------
3
but that dont make sense im so confussed please help

-
Im not sure if you are solving for x, but if you aren't, i may still be able to help.
If you're solving for x, here's what to do.

Remember the rule "what you do to one side of the equation you have to do to the other?" well that sort of applies here. What you do to the center, do to both of the other sides of the equations.
-8<5x+1<7 The equation
-8-1<5x<7-1 Subtract 1 first
-9<5x<6 Simplify
-9/5<5x/5<6/5 Divide by 5
-9/5 Basically these inequalities say that this particular value of x is greater than -9/5, which is why it says -9/5 Hope this helps.

-
-8 < 5x + 1 < 7

subtract 1 from all
-9 < 5x < 6
divide 5 to all
-9/5 < x < 6/5.
1
keywords: please,alg,help,need,I need help please alg. 2
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .