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Math 30P - Permutations and Combinations: Deck of Cards question
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# Math 30P - Permutations and Combinations: Deck of Cards question

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
i) Selection of no red = All black = C(8,4) = 8!/(4! x 4!= C(8,1) x C(8,......
From a deck of 52 cards, the 12 face cards and 4 aces are removed. From these 16 cards that are removed, 4 are chosen. How many combinations are possible that have at most 1 red card?

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Of the 16 cards selected, you have 8 red and 8 black.

So selection of atmost 1 red card is, Either the selection has no red or one red.

i) Selection of no red = All black = C(8,4) = 8!/(4! x 4!) = 70

ii) Selection of one red = Selection of one red x Selection of 3 black

= C(8,1) x C(8,3) = 8 x 56 = 448

Hence total number of combinations possible = 70 + 448 = 518
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