If 2p is the perpendicular distance from the origin to the line x/a+y/b=1,then a^2,8p^2,b^2 are in

1)AP
2)GP
3)HP
4)No such realtion exist

the given line bx+ay-ab=0
Hence, 2p=lb*0+a*0-abl/sqrt(a^2+b^2)
1/4p^2=(a^2+b^2)/a^2b^2
2/8p^2=1/b^2+1/a^2
a^2,8p^2,b^2 are in HP

2p is the perpendicular distance from the origin to the line x/a+y/b=1,then
(ab)^2 = (b^2 + a^2)*4p^2
OR (1/a^2 + 1/b^2) = 2/8p^2
OR 1/a^2, 1/8p^2, 1/b^2 are in AP
OR a^2, 8p^2, b^2 are in HP.