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Ellipse with foci at (0,+3) and endpoints of the major axis at (0,+4)
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# Ellipse with foci at (0,+3) and endpoints of the major axis at (0,+4)

[From: ] [author: ] [Date: 11-05-14] [Hit: ]
and the foci are at (0, ±3),a = √(b² - 3²) = √(16 - 9) = √(7).x²/7 + y²/16 = 1.......
Find the quation for the conic described
Ellipse with foci at (0,+3) and endpoints of the major axis at (0,+4)
p.s. the +3 and +4 are also - I just did not know how to type a + and - together.

Thank You!

-
The center is at the origin---it is halfway between the foci along the focal axis (here the y-axis). If the equation is

x²/a² + y²/b² = 1

and the foci are at (0, ±3), then b = 4 and

a = √(b² - 3²) = √(16 - 9) = √(7).

The equation is therefore

x²/7 + y²/16 = 1.
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