X-intercept of y= 5x^2-2x +4

i used the quadraic equation, and got (1plus or minus the square root of negative nineteen) over 5

which i can't graph... 8O

To find x-intercept, substitute y=0 in the given equation.
It becomes 5x^2-2x+4=0
On using quadratic equation formula, the values for x are found as:
1/5 +0.872i and 1/5 - 0.872i which are imaginary intercepts.....

dude those intercepts are complex