Can someone help me with this simultaneous equation

6 = 2y + 0.8x
2 = 0.2y +1.2x

i know what the answer should be x = 1.25 and y = 2.5 but i dont know how to get to it

(1) 6 = 2y + 0.8x
(2) 2 = 0.2y +1.2x

You see that the coefficient of y in (1) is 10 times the coefficient of y in (2). Recall that if a = b then 10a = 10b so multiply (2) by 10 on both sides

(3) 20 = 2y +12x

Now also recall that if a = b and c = d then a - c = b - d so subtract (1) from (3)

(4) 14 = 11.2x

Since 14/11.2 = 1.25, x = 1,25. Substituting this back in (3) gives

(5) 20 = 2y +12(1.25) = 2y + 15

(6) 2y = 20 - 15 = 5

And y = 2.5

6 = 2y + 0.8x........(1)
2 = 0.2y + 1.2x......(2) Multiply by 10
20 = 2y + 12x Now take (1) away from this
6 = 2y + 0.8x -
14 = 11.2x
14 / 11.2 = x
1.25 = x Substitute for x in (1)
6 = 2y + (0.8 * 1.25)
6 = 2y + 1
6 - 1 = 2y
5 = 2y
2.5 = y

Multiply second equation by 10, then subtract the result from the first equation.
Solve,.....x = 5/4......then solve ... y = 5/2

6 = 2y + 0.8x
2 = 0.2y +1.2x

6 = 2y + 0.8x
-20 = -2y -12x
-11.2x = -14
x = 1.25
2y = 5
y = 5/2