5therefore sub for Z at the top;S = 4 x Z = 4 x 0.5 = 2 2. (3 x Y)\(6 x Y) = 7\d3Y = 7Y = 7\3sub for Y;6 x Y = d6 x (7\3) = d14 = d3. Yes they form a proportion dont know how to explain it properly but i would have shown (using the above steps) how the left side (9\24) can become the left side (15\40)4. No (cant explain once more)5. x - 7\3 = -64\15x= (-64\15) + (7\3)x = -1 14\15 (or -29\15)6.......
27/7(7/12) = 9/4 - plugging 7/12 for x
27/12 = 9/4 - multiplication
9/4 = 9/4 - Reducing 27/12 to lowest coomon fraction
2 1/4 = 2 1/4 - Division
it checks and equals ( I would have done this in the step above but I like my vulgar or improper fractions as mixed numbers . Okay)
I hope this helps
1. 4\16 = s\8
in other words they are trying to say
(4 x Z)\(16 x Z) = s\8
where Z is the same number in both cases...you can show working like this :-
using the bottom part of the fractions (i cant remember the name for the bottom part atm lol);
16Z = 8
Z = 0.5
therefore sub for Z at the top;
S = 4 x Z
= 4 x 0.5
= 2
2. (3 x Y)\(6 x Y) = 7\d
3Y = 7
Y = 7\3
sub for Y;
6 x Y = d
6 x (7\3) = d
14 = d
3. Yes they form a proportion dont know how to explain it properly but i would have shown (using the above steps) how the left side (9\24) can become the left side (15\40)
4. No (cant explain once more)
5. x - 7\3 = -64\15
x = (-64\15) + (7\3)
x = -1 14\15 (or -29\15)
6. 3 6\7x = 2 1\4
x = 2 1\4 (divided by) 3 6\7
or (using improper fractions)
x = 9\4 (divided by) 27\7
(when dividing invert left fraction)
x = 9\4 x 7\27
x = 7\12
Just solve for the variable in question.
i.e.
3/6 = 7/d
3d/6 = 7 (Multiply both sides by d)
3d = 42 (Multiply both sides by 6)
d = 14 (divide both sides by 3)
3/6 = 7/14 - both equal 1/2 half, so there you go.
