Maths problem help & ( not sure what area it comes under)

a straight line graph of ln y against ln x. the line crosses the axes at A(0,3) and B(3.5,0)

A) Find an equation relating ln y and ln x
B) hence, or otherwise, express y in the form px^q, giving the values of the constants p and q to 3 significant figs

Help ???

(A)
To find the equation of the straight line, first find its slope
m = (3-0)/(0-3.5) = -3/3.5 = -6/7

Equation of the straight line with m=-6/7 passing through (0,3)

lny - 3 = (-6/7) (lnx)
lny = -(6/7)(lnx) + 3

(B)
lny = -(6/7)(lnx) + 3

e^(lny) = e^[(-6/7)lnx +3]
y = (e^3)[(e^lnx)^(-6/7)]
y= (e^3)x^(-6/7)
p = e^3
q= -6/7