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The product of three consecutive whole numbers is 999900. What is the smallest of the three numbers
[From: ][author: ][Date: 11-11-24][Hit: ]
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99
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x(x + 1)(x + 2) = 999900
x(x^2 + 3x + 2) = 999900
x^3 + 3x^2 + 2x - 999900 = 0
solve to find your real integer solution
1
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