Help me solve this differential equation!

1.y''+6y'=8
2.y'+ytgx=(cosx)^2

2.) y' + (tan(x))*y = cos²(x)

Integrating factor = e^(∫tan(x) dx) = sec(x)

Multiplying both sides by integrating factor:

y'*sec(x) + (sec(x)*tan(x))*y = cos(x)

d/dx[y*sec(x)] = cos(x)

y*sec(x) = sin(x) + C

y = cos(x)*(sin(x) + C)

1)
y[x] = (4 x)/3 - 1/6 e^(-6 x) C[1] + C[2]